Get 5 free video unlocks on our app with code GOMOBILE

Snapsolve any problem by taking a picture.

Try it in the Numerade app?

Answered step-by-step

$$x^{2}+6 x+4$$Which of the following is equivalent to the expression above?A) $(x+3)^{2}+5$B) $(x+3)^{2}-5$C) $(x-3)^{2}+5$D) $(x-3)^{2}-5$

Solved by verified expert

This problem has been solved!

Try Numerade free for 7 days

Like

Report

Official textbook answer

Video by Lily An

Numerade Educator

This textbook answer is only visible when subscribed! Please subscribe to view the answer

00:56

$$\left(x^{2}-3\right)-\left(-3 x^{2}+5\right)$$

Which of the following expressions is equivalent to the one above?

\begin{equation}

\begin{array}…

03:57

$$

x^{2}-8 x+5

$$

Which of the following is equivalent to the expression above?

A) $(x-4)^{2}-11$

B) $(x-4)^{2}+11$

C) $(x+4)^{2}-11$

D) $(x+4…

01:10

Simplify the expression.

$$

\frac{x^{2}-3 x+2}{x^{2}+5 x+6} \div \frac{x^{2}+x-2}{x^{2}+2 x-3}

$$

02:42

Use the three expressions at the right.

a. Which expressions are equivalent to $x^{2}-5 x+6 ?$

b. Which expression can be factored by grouping?

(i) $…

00:47

Which of the following represents the expression $\frac{x^{2}-3 x}{x^{2}-5 x+6} \cdot \frac{(x-2)^{2}}{2 x}$ in simplest form?

$$A.)\frac{x(x-3)}{2}$…

00:44

Which of the following expressions is equivalent to $3\left(x^{2}+2\right)-3 x(1-x) ?$

(i) $6+3 x$

(ii) $-3 x+6 x^{2}+6$

(iii) $3 x^{2}+6-3 x-3 x^{2}…

02:14

Simplify each expression.

$$

\frac{x}{x^{2}+5 x+6}-\frac{2}{x^{2}+4 x+4}

$$

01:01

Which of the following represents the expression $\frac{x^{2}-3 x}{x^{2}-5 x+6} \cdot \frac{(x-2)^{2}}{2 x}$ in simplified form?

(A) $\frac{x(x-3)}{2…

Transcript

So in order to get this equation into a similar for must answer format, it looks like we have to do something similar to completing two square, because all of the left left side so all the terms over here seem to be in a complete square. So in order to do that, we’re going to go ahead and think about this component first. And then we’re going to realize that in order to complete the square out of our X squared plus B X plus C term for just looking at the X scripless B X in order to complete the square, we just have to take the B and divide that by two and then square that whole quantity and then add that component to both sides of the equation formally, if we’re completing the square, so let’s go and try that. So if we have our b A six, that’s our be so we can say six Divided by two, which is three three squared is nine. So if we take X Square plus six X plus nine, then we would be able to get a pervasive where so then, if we were to put this into squares, we would get X Plus three swear. And…