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The vertex angle of an isosceles triangle has a measure of 68. If the length of the altitude drawn to the base is 14, find the length of the base and each leg of the triangle. Estimate your answers to two decimal places.

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00:31

Find the measure of the vertex angle of each isosceles triangle given the following information.The measure of one base angle is $68^{\circ} .$

05:04

The legs of an isosceles triangle are each $18 .$ The base is 14a. Find the base angles to the nearest degree.b. Find the exact length of the altitude to the base.

01:37

Solve each problem involving triangles.Find the altitude of an isosceles triangle having base $184.2 \mathrm{cm}$ if the angle opposite the base is $68^{\circ} 44^{\prime}$.

00:23

Find the measure of the vertex angle of each isosceles triangle given the following information.The measure of one base angle is $56^{\circ} .$

02:29

Solve each problem.Find the altitude of an isosceles triangle having base $184.2 \mathrm{~cm}$ if the angle opposite the base is $68^{\circ} 44^{\prime}$.

Transcript

we have an isosceles triangle that has a vertex angle Right here, that is 68°. So if we have an altitude, we’re going to bisect that angle. And we’re also going to create two congruent parts on the bottom. So we have a if the The length of the altitude is 14 and we want to find the length of the base and each leg of the triangle. So the legs are going to be the same. So I’m going to have to use some trig ratios here. So why don’t we first sulfur our hypotenuse and then solve for the bottom part here and double it to find the area or the length of the entire base. So to solve for the hypotenuse, X is going to be equal to the co sign Of 34°. Now the reason we’re using 30 for is because the entire angle of 68. So we’ll have the coastline of 34° is equal to adjacent over hypotenuse. So the co sign of 34° is equal to. So…

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