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Temperature can be measured in both Celcius scale(°C) and Fahrenheit scale(°F). The relation between both the scales is given by F =15(9C+160). If the freezing point of a liquid is −80°C, using the relation given above, find the freezing point of the same liquid in °F.Temperature can be measured in both Celcius scale(°C) and Fahrenheit scale(°F). The relation between both the scales is given by F =15(9C+160). If the freezing point of a liquid is −80°C, using the relation given above, find the freezing point of the same liquid in °F.

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01:21

Temperature can be measured in both the Celsius scale (Â°C) and the Fahrenheit scale (Â°F). The relation between both the scales is given by F = 9/5C + 32.If the freezing point of a liquid is -80Â°C, using the relation given above, find the freezing point of the same liquid in Â°F.

03:54

The relationship between temperature measured in the Celsius scale and the Fahrenheit scale is linear. The freezing point of water is 0Â°C and 32Â°F, and the boiling point is 100Â°C and 212Â°F.

(a) Find an equation giving the relationship between the temperature F measured in the Fahrenheit scale and the temperature C measured in the Celsius scale.F = (9/5)C + 32

(b) Use the formula from part (a) to determine the temperature in Fahrenheit corresponding to a temperature of 30Â°C. (Round your answer to one decimal place.)Â°F = (9/5)(30) + 32

(c) Find C as a function of F and use this formula to determine the temperature in Celsius corresponding to a temperature of 80Â°F. (Round your answer to one decimal place.)Â°C = (5/9)(80 – 32)

02:54

The Rankine temperature scale is an absolute temperature scale that uses Fahrenheit degrees; that is, temperatures are measured in Fahrenheit degrees, starting at absolute zero. Find the relationships between temperature values on the Rankine scale and those on the Fahrenheit, Kelvin, and Celsius scales.

02:36

Fahrenheit and Celsius In the Fahrenheit temperature scale, water freezes at $32^{\circ} \mathrm{F}$ and boils at $212^{\circ} \mathrm{F}$. In the Celsius scale, water freezes at $0^{\circ} \mathrm{C}$ and boils at $100^{\circ} \mathrm{C}$. Given that the Fahrenheit temperature $F$ and the Celsius temperature $C$ are related by a linear equation, find $F$ in terms of $C$. Use your equation to find the Fahrenheit temperatures corresponding to $30^{\circ} \mathrm{C}, 22^{\circ} \mathrm{C},-10^{\circ} \mathrm{C},$ and$-14^{\circ} \mathrm{C},$ to the nearest degree.

01:50

In the Fahrenheit temperature scale, water freezes at $32^{\circ} \mathrm{F}$ and boils at $212^{\circ} \mathrm{F}$. In the Celsius scale, water freezes at $0^{\circ} \mathrm{C}$ and boils at $100^{\circ} \mathrm{C}$. Assuming that the Fahrenheit temperature $F$ and the Celsius temperature $C$ are related by a linear equation, find $F$ in terms of $C$. Use your equation to find the Fahrenheit temperatures corresponding to $30^{\circ} \mathrm{C}, 22^{\circ} \mathrm{C},-10^{\circ} \mathrm{C}$, and $-14^{\circ} \mathrm{C}$, to the nearestdegree.

Transcript

The relationship between fahrenheit and celsius is the following: formula: f is equal to 9 fits c plus 32 point. So, given that we know what our temperature is in celsius, we can use this formula to help us calculate what it should be in fahrenheit for this particular problem. The question is asking: if the freezing point of a particular liquid is negative, 80 degrees celsius, then what is the temperature in degrees fahrenheit? So all we have to do here is replace the c in our formula with negative 80 point and that’s what i’m going to do. So we have f is equal to 9 fifth times negative 80 plus 32 point now. According…