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Chapter 6, Problem 13

From any point on a line perpendicular to a plane, two lines are drawn oblique to the plane. If the foot of the perpendicular is equidistant from the feet of the oblique lines, prove that the oblique segments are congruent.

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Video by Debasish Das

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Transcript

Question number 13 point here: it is given that there is a plane is there is a plane and there is a point outside the plane and you’re drawing it perpendicular to the plane, and also there are 2 blic lines and on to another 2 points on the Play and to stand between the base of the multiplier- and this are equal to this power equal. So you have to prove that these 2 bilanes are come on to each other. So far it is a. This is b c c. This is d, so let us start that up with the ray so statement is so is the name is not given me a time. The name. Let us go by the name given to a d is perpendicle. This is given so then you can say measurement triangle. A d c is equal to angle. A d v is equal to 90 degree and…

You are watching: SOLVED:From any point on a line perpendicular to a plane, two lines are drawn oblique to the plane. If the foot of the perpendicular is equidistant from the feet of the oblique lines, prove that the o. Info created by GBee English Center selection and synthesis along with other related topics.