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) Find the area of the parallelogram with vertices (1,1,1), (4,4,4), (8,-3,14), and (11, 0, 17)

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01:54

Find the area of the parallelogram with vertices $P(1,0,2),$$Q(3,3,3), R(7,5,8),$ and $S(5,2,7) .$

02:31

Find the area of the parallelogram whose vertices are $P_{1}, P_{2}, P_{3},$ and $P_{4}$.$P_{1}=(-2,1,6) ; \quad P_{2}=(2,1,-7) ; \quad P_{3}=(4,1,1) ;$$P_{4}=(8,1,-12)$

01:03

Find the area of the parallelogram with vertices $K(1,2,3),$ $L(1,3,6), M(3,8,6),$ and $N(3,7,3) .$

02:50

Find the area of the parallelogram with vertices $P_{1}, P_{2}, P_{3},$ and $P_{4}$.$$\begin{array}{l}P_{1}=(2,1,1), \quad P_{2}=(2,3,1), \quad P_{3}=(-2,4,1), \\P_{4}=(-2,6,1)\end{array}$$

03:50

Find the area of the parallelogram with vertices $ P (1, 0, 2), Q (3, 3, 3), R (7, 5, 8) $, and $ S (5, 2, 7) $.

Transcript

in this question. We have to find the area of the parallelogram in the world. This is a Cuban. So remember that the area of the parallelogram can be found by the cross product offers hs scent sites. So this these were this is our one comma one comma one, this is four comma four comma four, this is eight comma negative three comma 14 and this is 11 to 0 and 17. So we find this vector and we find this vector and we cross multiply these two vectors to the area. And for definitely the magnitude of this cross product is the area. So factor a is going to be uh the final position of minus initial positions of 4 -1 is three and that’s why it’s 333. And the actor B is going to be 8 -4 which is four and we have negative three minus four is negative seven. And…

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You are watching: SOLVED: ) Find the area of the parallelogram with vertices (1,1,1), (4,4,4), (8,-3,14), and (11, 0, 17). Info created by GBee English Center selection and synthesis along with other related topics.