Question 1 :

Plot the following points in the coordinate system and identify the quadrants P (–7, 6), Q (7, –2), R (–6, –7), S (3, 5) and T (3, 9)

Solution :

Point in quadrants 1st 2nd 3rd 4th |
General form (x, y) (-x, y) (-x, -y) (x, -y) |

P(-7, 6) lies in IInd quadrant

Q(7, -2) lies in Ist quadrant

R(-6, -7) lies in IIIrd quadrant

S(3, 5) lies in Ist quadrant

T(3, 9) lies in Ist quadrant

Question 2 :

Write down the abscissa and ordinate of the following from (i) P (ii) Q (iii) R (iv) S

Solution :

abscissa = The point on the x-axis

P (-4, 4)

Q (3, 3)

R (4, -2) and S (-5, -3).

Question 3 :

Plot the following points in the coordinate plane and join them. What is your conclusion about the resulting figure?

(i) (–5,3) (–1,3) (0,3) (5,3)

Solution :

Hence the given points are collinear. By joining the point, we get the straight line which is parallel to x-axis.

(ii) (0,–4) (0,–2) (0,4) (0,5)

Solution :

A straight line lies on y-axis.

Question 4 :

Plot the following points in the coordinate plane. Join them in order. What type of geometrical shape is formed?

(i) (0,0) (–4,0) (–4,–4) (0,–4)

Solution :

Let the given points be A (0,0) B(–4,0) C (–4,–4) and D(0,–4)

By joining the given points, we get a square.

(ii) (–3,3) (2,3) (–6,–1) (5,–1)

By joining the given points, we get the shape trapezium.

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