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Newton’s Laws Cheat sheet
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Timothy Welsh
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San Joaquin County Office of Education
Sep. 14, 2014

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14,496 views
Newton’s Laws Cheat sheet
Sep. 14, 2014

0 likes

14,496 views
Timothy Welsh
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San Joaquin County Office of Education
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Education
Cheat sheet
Newton’s Laws Cheat sheet
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Newton’s Laws Cheat sheet
AP Physics –
Core Concept Cheat Sheet 06: Newton’s Laws Key Physics Terms • Vector: A quantity that represents magnitude (size) and direction. It is usually represented with an arrow to indicate the appropriate direction. They may or may not be drawn to scale. • Resultant: the result of adding two or more vectors; vector sum. • Vector Component: The perpendicular parts into which a vector can be separated and that act in different directions from the vector. • Vector Addition: The process of combining vectors; added tip to tail. • Velocity: The distance an object travels per unit of time including its direction of motion. • Static Equilibrium: A motionless state where all the forces acting on an object yield a net force of zero. • Dynamic Equilibrium: A condition of constant motion, zero acceleration where all the forces acting on an object yield a net force of zero. • Friction Force: A force that acts to resist motion of objects that are in contact. • Normal Force: Support force that acts perpendicular to a surface. If the surface is horizontal, this force balances the weight of the object. • Force: A vector quantity that tends to accelerate an object; a push or a pull. • Net Force, Fnet: A combination of all the forces that act on an object. Variables Used • d = distance • t = time • v = velocity (usually average velocity or constant velocity) • a = acceleration • F = force • Ff =frictional force • FN =normal force • Δ = change in • Θ = angle • m = mass • μ = coefficient of friction • W = weight Key Formulas FN m θ F┴ F║ W Ff An inclined plane showing all the forces acting on RapidLearningCenter.com © Rapid Learning Inc. All Rights Reserved • v = d / t • a = Δv/Δt = (vf – vi)/t • d = vit + at2 /2 • vf 2 = vi 2 + 2ad • Pythagorean Theorem: c2 = a2 + b2 • Sin θ = opp / hyp • Cos θ = adj / hyp • Tan θ = opp / adj • Fnet = ma • μ = Ff / FN • Fnet = ΣF = the sum of all forces • For the vertical sign convention of up is positive: Acceleration due to gravity, g, = -9.8 m/s2 Key Metric Units • Time: seconds, s • Distance, m • Force: Newton’s, N • Mass: kilograms, kg • Velocity: m/s • Acceleration: m/s2, m/s/s • Coefficient of friction: no units Static vs. Dynamic Equilibrium • In static equilibrium, the net force on an object is zero; the object is also stationary. The forces balance out to leave the object motionless. • In dynamic equilibrium, the net force on an object is zero; however, the object is still moving at a constant velocity. The forces balance out to leave the object in its current state of motion with no accelerations or changes. Vector Diagram • Newton’s Laws • Newton’s 1st law: An object at rest tends to stay at rest, an object in motion tends to stay in motion; inertia. • Newton’s 2nd law: Fnet = ma. • Newton’s 3rd law: For every force there is an equal and opposite force; action and reaction. Newton’s Laws Problem Solving Tips • These tips will make it easier to solve any force related physics problems. • Thoroughly read the entire problem. • Draw a diagram if needed. Include a diagram to show all forces acting on a particular body. • Identify all given information. • Identify the quantity to be found. • Select appropriate formula(s) that incorporate what you know and what you want to find. • Convert units if needed. Use units throughout your calculations. • Do any mathematical calculations carefully. Typical Dynamics Problem Example: A model rocket of mass 3.0 kg has an engine that produces 100 N of upward thrust/force. What is the resulting acceleration of the model rocket when it is fired? Assume its mass is constant throughout its motion. Ignore any frictional forces. Known: Mass,m = 3.0 kg Upward force Fup = 100 N Unknown: Acceleration = ? m/s2 Define: First, find the weight of the rocket: Since we know its mass we can find its weight. W = mg Second, find the net force on the rocket: If upward force is positive, the weight is negative. Fnet = ΣF =Fup – W Then use F=ma and solve for a a = Fnet/m Output: W = 3.0 kg (-9.8 m/s2) = -29 N Fnet = ΣF =100 N – 29 N =71 N a= 71 N/ 3.0 kg = 24 m/s2 Substantiate: Units are correct, sig fig are correct, magnitude seems reasonable. How to Use This Cheat Sheet: These are the keys related this topic. Try to read through it carefully twice then write it out on a blank sheet of paper. Review it again before the exams.

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