I am not allowed on that page on webassign so i am using this table http://www.cem.msu.edu/~reusch/OrgPage/bndenrgy.htm &C http://chemistry.about.com/od/chartstables/a/bondenergytable.htm please check data if correct (a) NF3 1/2 N2 + 3/2 F2 ——> NF3 Hf = 3*(N-F) – (1/2)*(N-N + 3*F-F) = 3*(-272) -0.5*(- 38.4 -3*36.6) = -741.9 kJ /mol (b) H2N-NH2 N2 + 2H2 ——-> H2N-NH2 Hf = 4*(N-H) + N-N – N-N – 2*H-H = -4*93-(-2*104.2) = -163.6 kJ (c) F2C=CH2 2 C(graph) + F2 (g)+ H2 (g) ——> F2C=CH2 Hf = 2*(C-F) + 2*(C-H) + C=C – (F-F) – H-H + 2* ( graphite —> C(g)) = – 2*116 – 2*99 – 146 + 36.6 + 104.2 + 2*Can\’t find the data (d) CH3Cl C(graph) + 1/2Cl2 (g)+ 3/2H2 (g) —–> CH3Cl Hf = 3*(C-H) + C-Cl – 0.5*(Cl-Cl) – 1.5*(H-H) + ( graphite —> C(g)) Solution I am not allowed on that page on webassign so i am using this table http://www.cem.msu.edu/~reusch/OrgPage/bndenrgy.htm &C http://chemistry.about.com/od/chartstables/a/bondenergytable.htm please check data if correct (a) NF3 1/2 N2 + 3/2 F2 ——> NF3 Hf = 3*(N-F) – (1/2)*(N-N + 3*F-F) = 3*(-272) -0.5*(- 38.4 -3*36.6) = -741.9 kJ /mol (b) H2N-NH2 N2 + 2H2 ——-> H2N-NH2 Hf = 4*(N-H) + N-N – N-N – 2*H-H = -4*93-(-2*104.2) = -163.6 kJ (c) F2C=CH2 2 C(graph) + F2 (g)+ H2 (g) ——> F2C=CH2 Hf = 2*(C-F) + 2*(C-H) + C=C – (F-F) – H-H + 2* ( graphite —> C(g)) = – 2*116 – 2*99 – 146 + 36.6 + 104.2 + 2*Can\’t find the data (d) CH3Cl C(graph) + 1/2Cl2 (g)+ 3/2H2 (g) —–> CH3Cl Hf = 3*(C-H) + C-Cl – 0.5*(Cl-Cl) – 1.5*(H-H) + ( graphite —> C(g)).

You are watching: I am not allowed on that page on webassignso i am using this table.pdf. Info created by GBee English Center selection and synthesis along with other related topics.